Bue dal Vello d'Oro
 
Community Rating:
0.51.01.52.02.53.03.54.04.55.0
Community Rating: 5 / 5  (0 votes)
Card Name:
Bue dal Vello d'Oro
Mana Cost:
5Green
Converted Mana Cost:
6
Types:
Creatura Incantesimo — Bue
Card Text:
Costellazione — Ogniqualvolta il Bue dal Vello d'Oro o un altro incantesimo entrano nel campo di battaglia sotto il tuo controllo, una creatura bersaglio deve essere bloccata in questo turno, se possibile.
Flavor Text:
La tentazione di prendere il vello d'oro del bue è tanto irresistibile quanto fatale.
P/T:
5 / 4
Expansion:
Rarity:
Uncommon
Card Number:
125
Artist:
Rulings
4/26/2014 The defending player must assign at least one blocker to the target creature during the declare blockers step if that player controls any creatures that could block it.
4/26/2014 The constellation ability doesn’t force any specific creature to block the target creature.
4/26/2014 If multiple attacking creatures must be blocked if able, the defending player must assign at least one blocker to each of them if possible. For example, if two such creatures were attacking and there were two potential blockers, they couldn’t both be assigned to block the same attacker.
4/26/2014 A constellation ability triggers whenever an enchantment enters the battlefield under your control for any reason. Enchantments with other card types, such as enchantment creatures, will also cause constellation abilities to trigger.
4/26/2014 An Aura spell without bestow that has an illegal target when it tries to resolve won’t resolve and will be put into its owner’s graveyard. It won’t enter the battlefield and constellation abilities won’t trigger. An Aura spell with bestow won’t be countered this way. It will revert to being an enchantment creature and resolve, entering the battlefield and triggering constellation abilities.
4/26/2014 When an enchantment enters the battlefield under your control, each constellation ability of permanents you control will trigger. You can put these abilities on the stack in any order. The last ability you put on the stack will be the first one that resolves.